Question

If we divide the polynomial x4 + 4x3 + 2x2 + x + 4 by x2 + 3x, what will be the remainder?

Answer 1

`x^4+4x^3+2x^2+x+4 = Q(x)\cdot (x^2+3x)+ax+b,\;we\;need\;to\;find\;a,\;and\;b;\\\\x^4+4x^3+2x^2+x+4 = Q(x)\cdot x\cdot (x+3)+ax+b`

If you choose x = 0, then we have 4 = Q(0)*0 + a*0 + b, therefore b = 4.

If we choose x = -3, then we have:

`(-3)^4+4\cdot (-3)^3+2 \cdot (-3)^2-3+4 = Q(-3)\cdot (-3)\cdot (-3+3)-3a+4\Rightarrow 81-108+18+1=4-3a,\;or\;-12=-3a,\;so\;a=4.`

The remainder is: 4x+4.

Green eyes.