Find the area to the right of x=60 under a normal distribution curve with the mean=71 and standard deviation=6.

Ben Guest asked Apr 21, 2023

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Ben Guest asked Apr 21, 2023

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16 votes

Given that:

Mean = 71

Standard deviation = 6

To find

The Z-score for X is

$Z=(X-\mu)/(\sigma)$

Thus,

[tex]\begin{gathered} P(X>60)=P(Z>\frac{60-71}{6}) \\ =P(Z>-1.83) \\ =0.5+P(0From the standard normal table, P(0

Cerron answered Apr 25, 2023

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