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27 votes
27 votes
Jon said m-1 is always greater than 1-m do you agree?

User Vitaly Olegovitch
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1 Answer

17 votes
17 votes

Lets suppose that m-1 is always greater than 1-m. Then, we can write:


m-1>1-m

If we move -1 to the right hand side and -m to the left hand side, we get


m+m>1+1

which gives


2m>2

If we move the coefficient of m to the right hand side (2 is positive so it doesnt flip the inequality symbol) we have


\begin{gathered} m>(2)/(2) \\ m>1 \end{gathered}

Therefore, Jon is correct if and only if m is greater than 1.

User Eric Tjitra
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