Question

lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pulling to the right, a 36 N force that makesan angle of 30 deg with the horizontal-right.Calculate the net work done on the object. (1 point)A. O 462.747 JB. O1096.557 JC. O151.221 JD. O 675.066 J

Answer 1

The work done by a constant force in a rectilinear motion is given by:

`W=Fd\cos\theta`

where F is the magnitude of the force, d is the distance and θ is the angle between the force and the displacement vector.

In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:

`\begin{gathered} W=(17)(12)\cos0+(36)(12)\cos30 \\ W=578.123 \end{gathered}`

Therefore, the total work done is 578.123 J and the answer is option E