SOLUTION:
Case: Square-root of numbers
Given:
Required:
To find the square root to the nearest:
a) integer
b) tenth
Method:
a) integer.
We find the integer range for the square root of 46
![\begin{gathered} √(36)<√(46)<√(49) \\ 6x is a number closer to 7 than 6 because 46 is closer to 49<p>Hence;</p>[tex]√(46)\approx7(NearestInteger)]()
b) tenth
We find the tenth range for the square root of 46
![\begin{gathered} √(44.89)<√(46)<√(46.24) \\ 6.7x is a number closer to 6.8 than 6.7 because 46 is closer to 46.24<p>Hence:</p>[tex]√(46)\approx6.8(NearestTenth)]()
Final answers:
The square root of 46 is:
