Question

6. How many moles of O, will occupy a volume of 2.54 L at 2.56 atm and 28°C?

Answer 1

`0.26\text{ mol}`

Step-by-step explanation:

Here, we want to get the number of moles of oxygen that will occupy the given volume

To calculate that, we are going to use the ideal gas equation

Mathematically:

`\begin{gathered} PV\text{ = nRT} \\ n\text{ = }(PV)/(RT) \end{gathered}`

where:

V is the volume which is given as 2.54L

P is the pressure which is given as 2.56 atm

n is the number of moles that we want to calculate

T is the temperature which we would convert to Kelvin by adding 273 (273 + 28 = 301 K)

R is the molar gas constant which is 0.0821 L.atm/mol.K

Substituting the values, we have it that:

`n\text{ = }(2.56*2.54)/(301*0.0821)\text{ = 0.26 mol}`