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The length of a rectangle is 4 meters less than 3 times the width. If the perimeter is 128 meters, find the length and the width of the rectangle.

User Thrastylon
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1 Answer

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From the question, we can deduce the following:

Length of rectangle = 4 meters less than 3 times the width.

Perimeter of rectangle = 128 meters

Let'd find the length and width of the rectangle.

Let L represent the length and let W represent the width.

Thus, we have:

L = 3W - 4.......................equation 1

Apply the formula for perimeter of a rectangle:

P = 2W + 2L........................equation 2

Substitute 128 for P, and (3W - 4) for L in equation 2:

128 = 2W + 2(3W - 4)

Let's solve for W in the equation above.

Apply distributive property:

128 = 2W + 2(3W) + 2(-4)

128 = 2W + 6W - 8

128 = 8W - 8

Add 8 to both sides of the equation:

128 + 8 = 8W - 8 + 8

136 = 8W

Divide both sides by 8:


\begin{gathered} (136)/(8)=(8W)/(8) \\ \\ 17=W \\ \\ W=17 \end{gathered}

Therefore, the width of the rectangle is 17 meters.

To find the length of the rectangle, substitute 17 for W in equation 1:

L = 3W - 4

L = 3(17) - 4

L = 51 - 4

L = 47

Therefore, the length of the rectangle is 47 meters.

ANSWER:

• Width = 17 meters

,

• Length = 47 meters

User Edwinner
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