86,025 views
43 votes
43 votes
A projectile is launched from the ground at a 34 degree angle at 40m/S

A projectile is launched from the ground at a 34 degree angle at 40m/S-example-1
User Hiren Jungi
by
2.7k points

1 Answer

9 votes
9 votes

V = 40 m/sec and theta = 34

instead of (theta), i will write (O)

the projectile will come back to the ground at point (a, 0)

so,

y = V (sin O) * t + 0.5 * g * t^2

g = -9.8 m/sec^2

so,

0 = 40 sin 34 * t - 0.5 * 9.8 * t^2

0.5 * 9.8 * t^2 - 40 sin 34 * t = 0

4.9 * t^2 - 22.37 t = 0

solve for t :

take t as a common so, t ( 4.9 t - 22.37) = 0

t = 0 OR 4.9 t - 22.37 = 0

t = 22.37/4.9 = 4.565 sec

so, the projectile will come back to the ground again after 4.565 sec

to find the point at which the projectile come to the ground

x = V (cos O ) * t = 40 * cos34 * 4.565 = 151.38 m

User Msevgi
by
3.2k points