Question

A medical practice group consists of seven doctors, 4 women and 3 men. The women are Drs. Jonswold, Hein, O'Conell, and Lee. The men are Drs. Penner, Paquette, and Marland. Supposenew patients are randomly assigned to one of the doctors in the group.

Answer 1

The probability can be converted to percentage by multiplying it with 100. In our case, the probability is 3/7, which is equivalent to 0.428571. Then, by multiplying this number by 100, we get

`0.428571*100=42.8571\text{ \%}`

Therefore, by rounding to the nearest tenth, the answer is 42.9 %.