Question

A buffer solution is 0.451 M in H2SO3 and 0.386 M in NaHSO3. If Ka for H2SO3 is 1.7×10-2, what is the pH of this buffer solution?

Answer 1

You can either use an ice table or the Henderson-Hasselbalch equation. I would use the Henderson-Hasselbalch equation since that is the easiest method to use in my opinion. The Henderson-Hasselbalch equation is pH=pKa+log([A⁻]/[HA]).
pKa=-log(Ka) (which equals 1.77 in this question)
[A⁻]=concentration of conjugate base (0.386M in this question)
[HA]=concentration of acid (0.451M in this question)
When you plug everything in you should get a pH of 1.697.
I hope this helps. Let me know if anything is unclear or you want me to explain anything in more detail.