Question

A quantity of CO gas occupies a volume of 0.32 L at 0.90 atm and 323 K . The pressure of the gas is lowered and its temperature is raised until its volume is 3.8 L . Find the density of the CO under the new conditions. Express your answer to two significant figures and include the appropriate units.

Answer 1

Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol

Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)

Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K

d = 25.2 g / 26000 mL

d = .0.00096 g/mL is the density of CO under the new conditions