Question

A line passes through the points(-2,-6) and has a slope of - 5/2write an equation in slope intercept from for this line

Answer 1

We need to find the equation of the line passes through the points(-2,-6) and has a slope of - 5/2

The general equation of the line in slope - intercept form is :

`y=m\cdot x+b`

Where m is the slope and b is y - intercept

Given the slope = -5/2

so,

`m=-(5)/(2)`

We will find the value of b using the given point ( -2 , -6 )

so, the equation will be:

when x = -2 , y = -6

`\begin{gathered} -6=-(5)/(2)\cdot-2+b \\ \\ -6=5+b \\ b=-6-5 \\ \\ b=-11 \end{gathered}`

so, the equation of the line is:

`y=-(5)/(2)x-11`