Question

What is the point slope of an equation with slope of 3/5 that passes through the point (10,-2)

a. y-2=3/5 (x+10)

b.y+2=3/5 (x-10)

c.y-10=3/5 (x+2)

d.y+10=3/5 (x-2)

Answer 1

y - y_1 = m(x - x_1)
y - (-2) = 3/5(x - 10)
y + 2 = 3/5(x - 10)

The answer is B.

Answer 2

The answer would be B. It gives you the slope and a point on the graph so use that to your advantage. All of the answers show the slope and the slope in the right place, so for now it can be any of them. Then we get to the point (10,-2). For point slope form you would switch the signs for both x and y. So the Y would now be +2 and x would be -10. Y goes together with y, and X goes together with x. In this case y+-y= slope(X+-x) Substitute in for them. Y+2=3/5(X-10)