(3x²-7x+2)+(2x²+7x-1)

asked Mar 9, 2017 36.4k views

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$(3x^2 - 7x + 2)+(2x^2+7x - 1)=\\\\3x^2 - 7x + 2 +2x^2 + 7x - 1=\\\\3x^2+2x^2-7x+7x+2-1=\\\\\boxed{\bf{5x^2+1}}$

Nur answered Mar 11, 2017

by Nur

7.6k points

6 votes

3x^2+−7x+2+2x^2+7x+−1
Combine like terms:
3x^2+−7x+2+2x^2+7x+−1
(3x^2+2x^2)+(−7x+7x)+(2+−1)
Answer:
5x^2+1

Pirxpilot answered Mar 14, 2017

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