Question

What volume would a container need to be to hold 0.750 mol of neon at 5.00 atm at 325 K? (R = 0.0820574 L*atm/(mol*K))

Answer 1

`4.00\text{ L}`

Step-by-step explanation:

Here, we want to get the volume of the container needed

From the ideal gas law:

`\begin{gathered} PV\text{ = nRT} \\ V\text{ = }(nRT)/(P) \end{gathered}`

where:

V is the volume of the container that we want to calculate

n is the number of moles of Neon which is 0.750 mol

R is the molar gas constant which is 0.0820574

T is the temperature at 325 K

P is the pressure at 5 atm

Substituting the values:

`V\text{ = }(0.75*0.0820574*325)/(5)\text{ = 4 L}`