What is the momentum of a 2.5 x 10^6 kg train moving at 11.0 m/s?

Shanley asked Jan 27, 2023

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Shanley asked Jan 27, 2023

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20 votes

ANSWER:

27500000 kg*m/s

Explanation:

Given:

Mass (m) = 2.5x10^6

Speed (v) = 11 m/s

The formula to calculate the moment is as follows:

$\begin{gathered} p=m\cdot v \\ p=2.5\cdot10^6\cdot11 \\ p==27500000\text{ kg*m/s} \end{gathered}$

The moment is 27500000 kg*m/s

Smeshko answered Jan 31, 2023

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