Question

At STP, exactly 1 mole of any gas occupies 22.4 L. What size container (in Liters) do you need to hold 2.66 mol O2 gas at STP?(Show all work)59.647.763.870.3

Answer 1

Answer: A container with 59.6 L would be necessary to hold 2.66 moles of O2 (letter A)

Step-by-step explanation:

The question requires us to determine the volume of 2.66 moles of O2 at STP.

At standard temperature and pressure conditions (STP), 1 mol of any gas corresponds to 22.4 L of the gas. Thus, we can calculate the volume of 2.66 moles of O2 at STP as:

1 mol O2 --------------------- 22.4 L O2

2.66 mol O2 ---------------- x

Solving for x, we'll have:

`x=2.66mol\text{ O}_2*\frac{22.4L\text{ O}_2}{1mol\text{ O}_2}=59.6L\text{ O}_2`

Therefore, 2.66 moles of O2 at STP corresponds to 59.6 L of O2.