Question

How many real solutions does the equation x2 - 5 = 2x have?

Answer 1

ok

`\begin{gathered} \text{ x}^2\text{ - 5 = 2x} \\ x^2\text{ - 2x - 5 = 0 } \\ x^2\text{ -2x = 5} \\ x^2-2x+(1)^2\text{ = 5} \\ (x-1)^2\text{ = 5} \\ (x\text{ - 1) = }\sqrt[]{5} \\ x\text{ = }\sqrt[\square]{5}\text{ + 1} \\ x\text{ = 1 - }\sqrt[]{5} \end{gathered}`

It has two real solutions