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Please see attached photo for my problem from homework set. Thanks in advance!

Please see attached photo for my problem from homework set. Thanks in advance!-example-1
User Liath
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1 Answer

19 votes
19 votes

Question:

Solution:

a) Consider the following equation:


(x+4)(x-2)=7

applying the distributive property, we get:


x^2+2x-8\text{ =}7

now, putting all terms on one side of the equation, we get:


x^2+2x-8-7=0

this is equivalent to:


x^2+2x-15=0

Factoring this expression, we get:


(x-3)(x+5)=0

according to the equation, we can conclude that the solutions for the given equation are:


x\text{ = 3}

and


x=\text{ }-5

b) Consider the following equation:


6x^2+9x-22\text{ =0}

applying the quadratic formula:


\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

where

a = 6,

b = 9

and

c = -22,

we obtain that the solutions of the given equations are:


x\text{ =}\frac{-9+\sqrt[]{609}}{12}=\text{ 1.3}0

and


x\text{ =}\frac{-9-\sqrt[]{609}}{12}=\text{ -2.8}0

Please see attached photo for my problem from homework set. Thanks in advance!-example-1
User Xiao Han
by
3.0k points
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