Question

6. Write an equation of a parabola that opens to the left, has a vertex at the origin, and a focus at (-9,0).x- haveyou toy = -

Answer 1

A) x =-1/36y²

1) Considering that the Vertex is on the origin (0,0) and the Focus is at (-9, 0)

Then we can write out:

y² =-2px p is the parameter

F= (-p/2, 0) Since the Focus is at (-9,0)

-p/2 = 9

-p = 18

p= -18

`\begin{gathered} y^2=-2.18x \\ y^2=-36x\text{ } \\ or \\ x=-(1)/(36)y^2 \\ \end{gathered}`

2) Hence, the answer is x=-1/36y².