Question

Cyanide gas has a pressure of 6.0atm.If the pressure is decreased to 0.5atm and the final volume is 48L, what was the original volume?

Answer 1

The original volume of the gas is 4L

Step-by-step explanation

Given information

The initial pressure of the gas = 6.0atm

The final pressure of the gas = 0.5 atm

The final volume of the gas = 48L

Step 1: Write the Boyle's law formula

`\text{ P1}* V1\text{ = P2}* V2`

Where

P1 = 6.0 atm

P2 = 0.5 atm

V2 = 48L

V1 =?

Step 2: Substitute the given data into the formula in step 1

`\begin{gathered} 6.0* V1\text{ = 0.5}*\text{ 48} \\ 6.0\text{ }*\text{ V1 = 24} \\ \text{ Divide both sides by 6} \\ \text{ V1 = }(24)/(6) \\ \text{ V1 = 4L} \end{gathered}`

Hence, the original volume of the gas is 4L