Question

A train moves with a uniform velocity of 36 kmh-1 for 10 s. Find the distance travelled by it.

Answer 1

First we should convert
`36 km h^(-1)` to
`km s^(-1)`


`36 km h^(-1) = (36)/((60)(60)) = .01 km s^(-1)`

To find the distance travelled we use
`s = ut + (1)/(2) a t^(2)`
Where:

s = distance travelled

`u = .01 km s^(-1)` (velocity)
t = 10 s (time)

`a = 0 m s^(-2)` (acceleration)

By inserting these values into the equation we get:

`s = (.01)(10) + (1)/(2) (0) (10)^(2)`
= (.01)(10)
= .1 km