Question

What is the area of the sector of the circle below, if the radius is 9 cm and the central angle < AOB measures 37°. (round answer to the nearest tenth)

Answer 1

Given the figure of the circle O

As shown, the radius of the circle = r = 9 cm

The measure of the central angle < AOB = 37°

We will find the area of the shaded sector

We will use the following formula:

`Area\text{ }of\text{ }the\text{ }sector=(\theta)/(360)*\pi r^2`

Substitute θ = 37°, and r = 9

So, the area of the sector will be:

`(37)/(360)*\pi *9^2=26.1537588\text{ }cm^2`

Rounding to the nearest tenth

So, the answer will be: c. 26.2 cm²