Question

Tara has two bags of marbles. The first bag contains 5 red marbles. 4 blue marbles, and 6 green marbles. The second bag contains 3 red marbles, 2 blue marbles, and 4 green marbles. Tara will randomly select 1 marble from each bag.What is the probability that Tara will select a red marble from each bag?F. 5/9G. 1/9H. 3/5J. 2/3

Answer 1

Bag 1

Red = 5

Blue = 4

Green = 6

Total = 15

Bag 2

Red = 3

Blue = 2

Green = 4

Total = 9

`\begin{gathered} \text{Probability of an event = }\frac{n\text{ umber of required outcomes}}{n\text{ umber of possible outcomes}} \\ \text{For bag 1} \\ \text{Probability of selecting red marble from bag 1} \\ =\text{ }(5)/(15)\text{ = }(1)/(3) \\ \text{Probability of selecting red marble from bag 2} \\ =\text{ }(3)/(9)\text{ = }(1)/(3) \\ \\ \end{gathered}`

Therefore, Probability of selecting 1 red ball from each bag = red and red

`\begin{gathered} =\text{ }(1)/(3)\text{ x }(1)/(3) \\ =\text{ }(1)/(9) \end{gathered}`