Question

What two numbers add to 7 and multiply to 1044

Answer 1

xy=1044
x+y=7

y=7-x
sub
x(7-x)=1044
7x-x^2=1044
0=x^2-7x+1044
use quadratice equaiton which is if you have
ax^2+bx+c=0 then
x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}`

ax^2+bx+c=0
1x^2-7x+1044=0
a=1
b-7
c=1044

x=
`\frac{-(-7)+/- \sqrt{(-7)^(2)-4(1)(1044)} }{2(1)}`
x=
`(7+/- √(49-4176) )/(2)`
x=
`(7+/- √(-4127) )/(2)`
x=
`(7+/- √(-4127) )/(2)`
aprox
x=-3.5+32.120865492698i or
-3.5- 32.120865492698i
where i=√-1


so the numbers are -3.5+32.120865492698i and
-3.5- 32.120865492698i
where i=√-1

Answer 2

It's not possible.

Thus, either use the Quadratic Formula, or look for a new method to find the solution.

Quadratic Formula:


`x= \frac{-b(+/-) \sqrt{b ^(2) }-4ac }{2a}`.