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A theater has 37 seats in the first row, 39 seats in the second row, 41 seats in the third row, and so on. How many seats are there in row 18?

User Kaskader
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1 Answer

14 votes
14 votes

Given:

37 seats in the first row, 39 seats in the second row, 41 seats in the third row, and so on.

Given values can be written as a AP sequence.

37,39,41,...


a=37\text{ , d=39-37=2}
t_n=a+(n-1)d

When n=18


\begin{gathered} t_(18)=37+(18-1)(2) \\ t_(18)=37+34 \\ t_(18)=71 \end{gathered}

No of seats in row 18 are 71.

User Ram Narasimhan
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