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How do you solve for x in x^2+5x=36

User Pesama
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2 Answers

3 votes

Answer: (-9,4)

Step-by-step explanation: First, we set the equation equal to zero by subtracting 36 from both sides to get x² + 5x - 36 = 0.

Next, we factor the left side of the equation

as the product of two binomials.

Since the factors of -36 that add to +5 are +9 and -4,

we have (x + 9)(x - 4) = 0.

This means that either x + 9 = 0 or x - 4 = 0.

Solving each equation from here,

we have x = -9 or x = +4.

So your solution set is (-9,4).

How do you solve for x in x^2+5x=36-example-1
User Diaa
by
8.3k points
3 votes
First we want to set the equation equal to zero by subtracting 36 from each side...

x^2 + 5x -36 = 0

Now we factor

(x + 9)(x - 4) = 0

Now set each expression equal to zero and solve...

x + 9 = 0 x - 4 = 0
x = -9 x = 4

Your solution set is

(-9, 4)
User Suborx
by
8.1k points