The coordinates of the vertices of the original figure are
A(5, 0), B(0, 5), C(-5, 0), and D(0, -5)
Therefore OB = 5, and OA = 5
Since AOB is a right-angled triangle with hypotenuse AB,
then
Hence,
From the graph, we can see that
BD = 10 =AC
and AC is perpendicular to BD
Therefore the figure is a square,
Which means that
Hence the image of the figure under the transformation is also a square with the length of a side equal to the product of 0.8 and the length of side of a side of the original figure
That is
Therefore