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Factor completely: x^4 – 16 A. (x2 + 2)3(x – 2) B. (x2 + 4)(x + 2)(x – 2) C. (x2 + 4)(x2 – 4) D. (x + 4)(x – 4)
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Factor completely: x^4 – 16 A. (x2 + 2)3(x – 2) B. (x2 + 4)(x + 2)(x – 2) C. (x2 + 4)(x2 – 4) D. (x + 4)(x – 4)

User Zeb
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1 Answer

2 votes
x^4 - 16 =
(x^2 + 4)(x^2 -4) =
B. (x^2 + 4)(x + 2)(x -2)
User George Hernando
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