Question

Julian jogs 2 kilometers east, 4 kilometers north, and then 7 kilometers west. How far is Julian from his starting position, to the nearest tenth of a kilometer?

Answer 1

The correct answer is 6.4 kilometers for khan Academy

Explanation:

Answer 2

6.4 kilometer

==============================

Explanation:

See the attached figure.

Let Julian starts from point O (0,0)

Julian jogs 2 kilometers east ⇒ arrived to point A (2,0)

4 kilometers north ⇒ arrived to point B (2,4)

and then 7 kilometers west ⇒ arrived to point C (-5,4)

How far is Julian from his starting position?

So, it is required to find the distance OC

From the graph OC =
`√((-5)^2+(4)^2)=√(25+16)  =√(41) =6.403`

So, the distance from his starting position ≈ 6.4 km (to the nearest tenth of a kilometer)