Question

A=(f+g/2)h ,solve for g

Answer 1

`A=(f+(g)/(2))h\ \ \ |Multiply\ h\ by\ each\ factor\ in\ bracket\\\\ A=fh+(gh)/(2)\ \ |*2\\\\ 2a=2fh+gh\ \ \ | Subtract \ 2fh\\\\ 2a-2fh=gh\ \ \ |Divide\ by\ h\\\\ (2a-2fh)/(h)=g\\\\ \boxed{g=(2(a-fh))/(h)}`

Answer 2

`A=(f+g)/(2)*h \\ \\ 2A=h(f+g) \\ \\ f+g=(2A)/(h) \\ \\ \boxed{g=(2A)/(h)-f}`