Question

(question 4 only plz)

Answer 1

#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks

a) P(white) =
`(2)/(6) = (1)/(3)`
P(red) =
`(1)/(6)`
P(purple) =
`(3)/(6) = (1)/(2)`

b)Not white block:
1 -
`(1)/(3)` OR
`(1)/(2) + (1)/(6)`

`(2)/(3)`
`(2)/(3)`
Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.

c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12

P(white)=
`(4)/(12)` which is still
`(1)/(3)`

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12

P(purple)=
`(5)/(12)`
(im not quite sure if my explanation here helps you though)

e) 1 more of white and purple, 5 more of red
white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)

P(red)=
`(6)/(12)` =
`(1)/(2)`