Question

how much potassium bromide, in grams, should be added to water to prepare 0.50 of solution with molarity of 0.125M?

Answer 1

Volume = 0.50 L

Molar mass KBr = 119.002 g/mol

Molarity = 0.125 M

Mass ( KBr) = ?

mass = molarity * molar mass * volume

mass = 0.125 * 119.002 * 0.50

mass = 7.437625 g of KBr

hope this helps!