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What is the mass of 4.23×10^23 atoms of iron
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What is the mass of 4.23×10^23 atoms of iron

User Nikhilesh
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1 Answer

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First divide atoms by Avogadro's number:
(4.32x10^23)/(6.02x10^23) = .703mol Fe

Then multiply moles by its molar mass:
(0.703mol Fe)(55.85g/mol Fe) = 39.24g Fe
User Fileunderwater
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