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The random variable X is exponentially distributed, where X represents the waiting time to see a shooting star during a meteor shower. If X has an average value of 85 seconds, what are the parameters of the exponential distribution

User Quetzaluz
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1 Answer

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Answer:

the parameters are
\lambda = (1)/(85) , \mu = 85, \sigma = 85

Explanation:

The computation of the parameters of the exponential distribution is as follows:

Given that

X has an average value of 85 seconds

So,
\mu = mean = 85


\lambda = (1)/(\mu)\\\\= (1)/(85)


\sigma = \mu = 85

In the case of the exponential distribution, the mean would be equivalent to the standard deviation

So, the parameters are
\lambda = (1)/(85) , \mu = 85, \sigma = 85

User Riskop
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