Question

_____Cl2 (g) + _____SnI4 (aq) → _____I2 (g) + _____SnCl4 (aq)How many moles of Tin (IV) Chloride are produced from 100.g of chlorine gas?

Answer 1

0.705moles

Explanations:

Given the balanced chemical reaction between Chlorine and SnI4 as shown:

`2Cl_2(g)+SnI_4(aq)\rightarrow2I_2(g)+SnCl_4(aq)`

Determine the moles of chlorine gas

`\begin{gathered} moles\text{ of Cl}_2=\frac{Mass}{molar\text{ mass}} \\ moles\text{ of Cl}_2=(100g)/(70.906) \\ moles\text{ of Cl}_2=1.41moles \end{gathered}`

According to stoichometry, 2moles of chlorine gas produces 1 mole of Tin(IV)chloride, the moles of Tin(IV)chloride produced will be:

`\begin{gathered} moles\text{ of SnCl}_4=(1)/(2)*1.41moles \\ moles\text{ of SnCl}_4=0.705moles \end{gathered}`