Question

How many moles of silver (Ag) are present in a sample of 3.8 × 1024 atoms Ag?

Select one:
a. 1.6 mol Ag
b. 2.3 mol Ag
c. 6.3 mol Ag
d. 22.8 mol Ag

Answer 1

1 mol=6.022 x 10²³ atoms.

1 mol-----------------------------6.022 * 10²³ atoms
x--------------------------------3.8 * 10²⁴ atoms

x=(1 mol * 3.8 * 10²⁴ atoms) / 6.022*10²³ atoms=6.3 moles of Ag,

Answer: C. 6.3 mol Ag

Answer 2

Answer : The correct option is, (C) 6.3 mole Ag

Explanation : Given,

Number of atoms of Ag =
`3.8* 10^(24)`

As we know that, 1 mole contains
`6.022* 10^(23)` number of atoms.

As,
`6.022* 10^(23)` number Ag atoms present in 1 mole of Ag

So,
`3.8* 10^(24)` number Ag atoms present in
`(3.8* 10^(24))/(6.022* 10^(23))=6.3` mole of Ag

Therefore, the number of moles of Ag present are, 6.3 moles