Question

I did some of it can you help me finish the rest

Answer 1

From the image given, we can read the y-intercept, calculate the slope, and derive the equation of the line as follows:

- y-intercept = c = -2 (since the graph intercepts the y axis at -2)

- slope:

`\text{slope}=m=(y_2-y_1)/(x_2-x_1)`

consider the points: (x1, y1) = (0, -2) and (x2, y2) = (-3, -1)

Thus:

`\begin{gathered} \text{slope}=m=(y_2-y_1)/(x_2-x_1)=\frac{-1_{}-(-2)}{(-3)_{}-0_{}}=(-1+2)/(-3-0)=(1)/(-3) \\ \Rightarrow\text{slope}=m=-(1)/(3) \end{gathered}`

- Now, the equation of the line is:

`y=mx+c`

Thus:

`y=-(1)/(3)x+(-2)`
`\Rightarrow y=-(1)/(3)x-2`