Question

I'm stuck with this simultaneous equation. Can anyone help me please?

h + 3t = -10
2h - t = -8

Answer 1

Would use elimination method.

h + 3t = -10 ×2
2h - t = -8

2*(h + 3t) = 2*(-10)
2h + 6t = - 20......new equation 1.

2h + 6t = -20
-
2h - t = -8 To eliminate h.
__________
0 + 7t = -20 - -8

7t = -20 + 8

7t = -12

t = -12/7

From first equation: h + 3t = -10, substitute, t = -12/7

h + 3*(-12/7) = -10
h - 36/7 = -10
h = -10 + 36/7
h = 36/7 - 10

h = (36 - 70)/7
h = -34/7

Therefore, t= -12/7 and h = -34/7

Answer 2

multiply (h+3t= -10) to get 2h+6t=-20.

(2h+6t=-20) - (2h+t=-8) to get 5t=-28
therefore t=-5.6

put t into any equation. i.e (2h-t=-8) = 2h+5.6=-8
therefore 2h = -13.6
h=-6.8