Answer: Jane has a total number of 30 Nickels
Let the number of nickel coins = N
Let the number of quarters be = D
A nickel worth 5 cent
A quarter woth 25 cent
Since, jane had 36 coins and the coins contain both nickel and quarters
Therefore,
N + D = 36----------------- equation 1
0.05N + 0.25D = 3------------- equation 2
These two linear equation can be solve simultaneously by using substitution method
Make D the subject of the formula in equation 1
D = 36 - N
Substitute the value of D into equation 2
0.05N + 0.25(36 - N) = 3
Open the parenthesis
0.05N + 9 - 0.25N = 3
Collect the like terms
0.05N - 0.25N = 3 - 9
-0.2N = -6
Divide both sides by -0.2
-0.2N/-0.2 = -6/ -0.2
N = 30
Therefore, Jane has a total number of 30 Nickels