Question

I have been trying to figure this out and I keep getting answers that aren’t any of the answers on the slide. Can you help me?

Answer 1

Step-by-step explanation

Given that

`\begin{gathered} radius=15 \\ length\text{ of one side=9.3} \end{gathered}`

First we will find the perimeter of the decagon.

`p=10*9.3=93`

We will then find the height of one of the triangles of the decagon

`\begin{gathered} 15^2=h^2+9.3^2 \\ h^2=225-86.49 \\ h=√(138.51) \\ h=11.769027 \end{gathered}`

Therefore, the area of the polygon is ten times one of the triangle is