Solution
We can do the following
m arc DF = m < DEF = 50º
Similarly:
< BFA is a central angle then :
m arc BA = m < BFA = 70º
We also know that Ac is a diameter then arc BC is a semicircle then:
m arc BC = 180 -70 = 110º
m arc CD = 70º
Then :
m arc AE = 180 -50-70 = 60º
And the final answer is:
m arc AC = 180º (semicircle)
m arc AE = 60º (minor)
m arc BD = 110 + 70 = 180º (semicircle)