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How much does 4.35x10^24 atoms of selenium weight?

User JosephL
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1 Answer

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Step-by-step explanation:

To solve this question, we need to know the Avogadro's constant:

6.022 x 10^23 atoms equal 1 mol.

So, in this case we have 4.35x10^24 atoms of selenium.

We first transform it to moles and then to grams, using the following formula:

m = n*MM

where:

m = mass

n = moles

MM = molar mass of selenium = 78.96 g/mol

6.022 x 10^23 ---- 1 mol

4.35x10^24 ---- x mol

x = 7.22 moles

m = 7.22 * 78.96

m = 570.4 g

Answer: m = 570.4 g

User Abelisto
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