2x-y=16 8y=4(4x-32) what are the solutions to the following systems of equations?

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2x-y=16
8y=4(4x-32)
what are the solutions to the following systems of equations?

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22 votes

Answer: y = 2x - 16 for both

Explanation:

1. 2x-y=16
-y=-2x+16

y = 2x - 16
8y=4(4x-32)

8y=16x-128

y = 2x - 16

Jpseng answered Mar 2, 2023

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