Question

Write an equation for the line that parallel to the given line. And that passes through the given point Y=-6x+2;(-1,2)A. Y=-6x-4B. Y=6x -8 C. Y=-6x+4D. Y=-8x-8

Answer 1

find the equation of the line parallel to the line y=2−6x passing through the point (−1,2).

The equation of the line in the slope-intercept form is y=2−6x

The slope of the parallel line is the same, m = -6

So, the equation of the parallel line is: y = -6x + a

To find a, we use the fact that the line should pass through the given point: 2 = -6 * (-1) + a

Thus, a = -4

Therefore, the equation of the line is

`y=-6x-4`