Question

10. If the area of square 1 is 25 units, and thearea of square 2 is 16 units2, what is theperimeter of square 3?

Answer 1

Given:

The area of square 1 is 25 square units.

Its length of the side is,

`\begin{gathered} A=s^2 \\ 25=s^2 \\ s=\pm5 \\ s=5\text{ ( since length can not be negative)} \end{gathered}`

The area of square 2 is 16 square units.

Its length of the side is,

`\begin{gathered} A=s^2 \\ 16=s^2 \\ s=\pm4 \\ s=4\text{ ( since length can not be negative)} \end{gathered}`

It gives,

Consider the right triangle,

`\begin{gathered} 5^2=4^2+x^2 \\ 25-16=x^2 \\ x^2=9 \\ x=\pm3 \\ x=3\text{ ( since length can not be negative)} \end{gathered}`

So, the length of square 3 is 3 units. Its perimeter is given as,

`\begin{gathered} P=4x \\ P=4*3 \\ P=12\text{ units} \end{gathered}`

Answer: the perimeter of square 3 is 12 units.