Question

Can you help me solve this question ASAP please and thank you

Answer 1

Let us revise some rules of log

`\log (a)+\log (b)=\log (a)(b)`
`\log (a)-\log (b)=\log ((a)/(b))`

Let us use these rules to solve the question

The given expression is

`\log (2)-\log (6)`

By using the 2nd rule

`\log (2)-\log (6)=\log ((2)/(6))=\log ((1)/(3))`

Also, we can use the first rule when chang log(6) to -log(1/6)

`\begin{gathered} \log (2)-\log (6)=\log (2)-\lbrack-\log ((1)/(6))\rbrack \\ \log (2)-\log (6)=\log (2)+\log ((1)/(6)) \end{gathered}`

By using the first rule

`\log (2)-\log (6)=\log (2)+\log ((1)/(6))`

The correct answers are C and D