Question

A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molarity (molar concentration) of the solution.

1.) 3 x 10 -5M
2.) 3 x 10 -2M
3.) 4 x 10 -1M
4.) 1 x 10 -4M

Answer 1

Volume in liters:

4,000 mL : 4,000 / 1000 = 4.0 L

Molar mass AgNO₃ =169.87 g/mol

Mass of solute = 17.00 g

Number of moles:

n = mass of solute / molar mass

n = 17.00 / 169.87

n = 0.10007 moles

Molarity = moles of solute / volume

M = 0.10007 / 4.0

= 3x10⁻² M

answer 2)

hope this helps!