Question

The force between a pair of 0.001 C charges is 200 N. What is the distance between them?

Answer 1

From Columb's Law which describe the electrostatic interaction.
The formula is given and looks as follows
`F=k (|q1*q2|)/(r^(2) )`
where:
F is force acting between charges,
q1 - charge one given in columbs,
q2 - charge two given in columbs,
r - distance between charge in meters
k - constant

First, we have to convert out formula to get r.

`F=k (q1*q2)/(r^(2) )`
Now we multiplaty by
`r^(2)` both sides of equation

`F* r^(2) =k*|q1*q2|`
Now we devide both sides by F

`r^(2) =k (|q1*q2|)/(F)`
Next step is take square root

`r= \sqrtq1*q2`
We have all date, we can subsitute it to our formula

`r= \sqrt{k* (|q1q2`