A six−sided die, with sides numbered 1,2, 3,4,5, and 6, is tossed. What is the probability of tossing a number less than three?

asked Jan 18, 2015 166k views

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$the \ probability= (the \ number \ of \ favorable \ cases)/(the \ number \ of \ posibble \ cases) \\ \\ \boxed{p=(2)/(6)= (1)/(3)}$

Pathoschild answered Jan 24, 2015

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